a car of mass 800kg is moving with a velocity of 90km/hr and when we apply break it stops at 50m find the retardation force on car
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M=800
V=90km/hr=90*5/18=25m/s
III Eqn of motion-
V^2-u^2=2as
25*25=2*a*50
a=25/4 m/s^2
F=m*a
F=800*25/4
Retardation force=5000N.
V=90km/hr=90*5/18=25m/s
III Eqn of motion-
V^2-u^2=2as
25*25=2*a*50
a=25/4 m/s^2
F=m*a
F=800*25/4
Retardation force=5000N.
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