A car of mass 800kg is travelling with a velocity of 20 m/s. When brakes are applied,it stops after travelling a distance of 8 meters. Find Retardation and Retarding force? A force of 2N acting on a body changes its velocity uniformly from 2 m/s to 5 m/s in 10s. Calculate the mass of the body. Calculate the change in momentum of a body weighing 5kg when its velocity decreases from 20m/s to 5 m/s?(Hint: Calculate P2- P1) What would be force required to produce an acceleration of 2m/s2 on a body of mass 12kg? A ball freely falling from a tower of height 5 m . How much momentum does it transfer to the floor if its mass is 5kg?
Answers
Answer:
s=(v+u)/2*t
8=10t
t=10/8s
retardation=20/10/8
=16m/s^2
regarding force =16*800
=2400N
2 ans.
a=(5-2)10
=3/10m/s^2
f=ma
2=m*3/10
m=20/3kg
3 ans...
p1= 5*5
=25kg.m/s
p2=5*20
=100kg.m/s
p2-p1
change of p=75kg m/s
4ans
f = ma
=12*2
=24N
5 ans
v =√2gh
=√100
p=50 kg m/s
Answer:
A car of mass 800kg is travelling with a velocity of 20 m/s. When brakes are applied,it stops after travelling a distance of 8 meters. Find Retardation and Retarding force?
A)mass(m)=800kg
initial velocity (u)=20 m/s
final velocity (v) =0 m/s
distance(s)= 8m
We have to find acceleration which is the retardation.
2as = v square - u square
2a×8 = 0 square × 20 square
16a= - 400
a=-400/16
a= -25 m/s
Retarding force:
F=ma
F= 800 × (-25)
F= -20000N
A force of 2N acting on a body changes its velocity uniformly from 2 m/s to 5 m/s in 10s. Calculate the mass of the body.
A)Force (F) = 2 N
Initial velocity (u) = 2 m/s
Final velocity (v) = 5 m/s
Time interval (t) = 10 sec
Solution :
v=u+at
a=v-u/t
a=5-2/10
a=3/10
a=0.3
So,
F=ma
m=f/a
m=2/0.3
Mass = 6.67
Calculate the change in momentum of a body weighing 5kg when its velocity decreases from 20m/s to 5 m/s?(Hint: Calculate P2- P1)
A)Momentum p=m×v
Initial momentum is
P1 = 5×20 = 100 kg m/s
Final momentum is
P2 = 5×0.20=1 kg m/s
So, change in momentum is
∆P = P2-P1 = 1 - 100 = -99 kg m/s
What would be force required to produce an acceleration of 2m/s2 on a body of mass 12kg?
Mass of the body A, m₁ = 10 g
= 10 × 10⁻³ kg
Mass of the body B, m₂ = 20 g
= 20 × 10⁻³ kg
Acceleration of body A, a₁ = 5 m/s²
Acceleration of body B, a₂ = 2 m/s²
F = ma
Force of body A, F(A) = m₁a₁ = 10 × 10⁻³ × 5
F(A) = 5/100 = 0.05 N
Force of body B, F(B) = m₂a₂ = 20 × 10⁻³ × 2
F(B) = 4/100 = 0.04 N
Since F(A) > F(B), therefore, we need force to accelerate A of mass 10 g.
Pls mark me as brainliest