a car of mass 800kg moving at 54 kmph is brought to rest over a distance of 15m. Find retarding force developed by brakes of car
(20 points)
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Answered by
74
given
m=800kg
u=54kmph=15m/s
v=0
by 3 equation of motion
v^2=u^2+2as
0= 225 + 2*a*15
-225/2*15=a
a=-15/2 ms^-2
we know that
F=ma
=800*(-15/2)
= -6000N
m=800kg
u=54kmph=15m/s
v=0
by 3 equation of motion
v^2=u^2+2as
0= 225 + 2*a*15
-225/2*15=a
a=-15/2 ms^-2
we know that
F=ma
=800*(-15/2)
= -6000N
Answered by
14
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