Question

a car of mass 90 kg starts from rest and acquires a velocity of 5 metre per second in 6 seconds. Calculate the force applied by the object.​

Answer 1

Answer:

THE FORCE IS OF 74.7 newton

Explanation:

Given , m=90kg

v=5m/s

I=0m/s

time taken in going from u to v =6s

AS , WE KNOW THAT

$f = ma$

so, we have to find acceleration.

as, we know that

$a =( v - u) \div t$

substituting the values of v,u and t in this equation :

$a = (5m/s \: - 0m/s) \div 6s</p><p></p><p>$

$= 5m/s + \div 6s</p><p>$

$= 0.83m/s ^{2} </p><p>$

substituting m=90kg and a= 0.83m/s^2 in f= ma

$f = 90kg \times 0.83m/s ^{2} </p><p>$

$= 74.7 newton$

that >p<>p is a glitch , neglect it

Answer 2

Given,

Mass (m) = 90 kg

Assuming that the initial velocity is 0 m/s,

Final Velocity (v) = 5 m/s

Time (t) = 6 s

Acceleration (a) = (v-u)/t

= (5-0)/6 m/s²

= 5/6 m/s²

= 0.834 m/s²

Force = ma

= (90*0.834) N

= 75.06 N

The Force applied is 75.06 N.

I hope this helps.