A car of mass 900 kg is moving with a velocity of 72km/hr. The driver applied brake and the car stops after 3 seconds. a. What is the retardation of the car?
b. Calculate the distance covered by the car.
c. Calculate the force needed to stop the car.
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Answer:
Mass of the car =2400 kg
Initial velocity u=20 m/s
Final velocity v=0 m/s
Time t=10s
Retardation a=tv−u=100−20=−2m/s2
Force =m×a=2400×2=−4800N.
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