a car of mass 900 kg moving with velocity of 72 km/hour is stopped at distance of 300m. Find breaking force
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v , final velocity = 0
u , initial velocity = 72 km/h = 20 m/s
s = 300m
m = 900kg
According to the equation given above ,
0 = (20)^2 - 2×a×300
0 = 400 - 600a
600a = 400
a = 400/600 m/s^2
a = 2/3 m/s^2
We know that,
F = m ×a
= 900 × 2/3
= 600 N
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