A car of mass 900kg is travelling at a steady speed of 90 m/s against a resistive 2000N find 1) kinetic energy of car 2)what is the minimum power that is the car engine has to deliverd to drive a car
Answers
Answered by
1
give
V = 90 m/s
K.E = 1/2 mV^2
K.E = 1/2 •900•8100
= 3645000 kg.m^2/s^2
sum of all force acting on car should be less than force acting by engine
F > 2000 + mg
F > 2000+ 900×9.8
F> 10820 N
hence
Power = F•V = 10820× 90
= 973800 Kg•m^2•s-3
V = 90 m/s
K.E = 1/2 mV^2
K.E = 1/2 •900•8100
= 3645000 kg.m^2/s^2
sum of all force acting on car should be less than force acting by engine
F > 2000 + mg
F > 2000+ 900×9.8
F> 10820 N
hence
Power = F•V = 10820× 90
= 973800 Kg•m^2•s-3
Similar questions