Question

A car of mass m is moving on a level circular track of radius R. If us represents the static friction between the road and tyres of the car,the maximum speed of the car in circular motion is given by?

Answer 1

Answer:

Explanation:v^2/r=us*g

V=√us rg

Answer 2

The expression for the circular motion is given by $\sqrt{\mu sRg}$.

Explanation:

• It is given that the car is moving on the road surface with maximum speed and has a of weight of m.
• μs is the expression used for static friction and due to presence of circular track there is a centripetal force in action.
• $V_{max}= F_{max}$ = Fl so the frictional force that is static and is present between the tyre and the road.
• So from this we get $\frac{MV^2}{R}$ = $\sqrt{\mu sRg}$  which results into $V_{max}$= $\sqrt{\mu sRg}$ .

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