Question

A car of mass M is moving with a uniform velocity uo on a horizontal road when the thief drops himself on it from building above. Taking the mass of the thief to be m, what will be the velocity of the car after the event?

Answer 1

Answer:

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Explanation:

Solution

Consier the car plus the hero s the system. IN the horizontla direction, thee is no exterN/Al fore. Since the hero has fallen vertically, so his initial horizontal momentum=0

Initila horizontla momentum of the system =Mv towards right.

FiN/Ally hte heor sticks of to the roof of the car so they move with equal horizontal velocity say V. FiN/Al horizontal momentum of teh system

=(M+m)V

Hence,Mv=(M+m)V

or, V=(Mv)/M+m`