Question

A car of mass m starts from rest and acquires a velocity along east v = vî (v > 0) in two seconds. Assuming the car moves with uniform acceleration, the force exerted on the car is​

Answer 1

Answer:

Solution:

A car of mass m starts from rest and acquires a velocity along east υ=υˆi(υ>0) in two seconds Assuming the car moves with unifrom acceleration the force exerted on the car is . This is due to friction on the tyres exerted by the road . ..lThe coefficient of static friction between the block and the surface is 0.6.

Explanation:

Here, Mass of the car =m

Initial velocity, u=0 (as the car starts from rest)

Final velocity v=v i^ along east

t=2s

Using

$v = u \: + \: at \: ⇒ \: vi \: = 0 + \frac{}{a} \times 2 \: or \: \frac{}{a} = \frac{v}{i} \huge {i} \\ \frac{}{F } = m \: \frac{}{a} = \frac{mv}{2} \huge{i} = \\ \frac{mv}{2} eastward \: </p><p></p><p>$

This is due to the friction on the tyres exerted by the road.

Answer 2

Answer:

A car of mass m starts from rest and acquires a velocity along east υ=υˆi(υ>0) in two seconds Assuming the car moves with unifrom acceleration the force exerted on the car is . This is due to friction on the tyres exerted by the road . ... The coefficient of static friction between the block and the surface is 0.6

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