Question

A car of mass m with the momentum p if nyu be the coefficient of the friction then at what distance car will stop by friction alone

Answer 1

$\Large\mathfrak{\underline{\underline{Answer:-}}}$

$\bold{\Rightarrow Distance=\frac{p^2}{2m^2\mu\:g}}$

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$\small\mathfrak{\underline{\underline{Step-By-Step\:Explanation:-}}}$

Let the distance covered be x

Conserving Energy

Initial Energy = Final Energy

$\bold{\Rightarrow\frac{p^2}{2m}=\mu\:mgx}$

$\bold{\Rightarrow\:x =\frac{p^2}{2m^2\mu\:g}}$

Since we know $\bold{ KE=\frac{p^2}{2m}}$

Hence, the distance covered by car is $\bold{\frac{p^2}{2m^2\mu\:g}}$

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MOMENTUM-

The quantity of motion of a moving body, measured as a product of its mass and velocity

momentum= mass × velocity

COEFFICIENT OF FRICTION-

A coefficient of friction is a value that show the relationship between force of friction between two objects and the normal force between the objects.

The coefficient of friction is dimensionless