A car of mass2400kg moving with avelocity 20 ms is stopped in 10 sec
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Answered by
0
-4800N is the force
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Answered by
1
If you’re force required to stop the car then
F = mΔv/t
= [2400 kg × (20 - 0) m/s] / (10 s)
= 4800 N
= 4.8 kN
4.8 kN Force is required to stop the car.
F = mΔv/t
= [2400 kg × (20 - 0) m/s] / (10 s)
= 4800 N
= 4.8 kN
4.8 kN Force is required to stop the car.
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