Physics, asked by rilangsyiem794, 8 months ago

A car P travelling at 90 kmh‐¹and is stopped by the application of breakes in 6 s .Another carQ travelling at 54 kmh‐¹ is stopped by the application of brakes in 10 s . Plot the motion of car P and Q on the same graph paper and then calculate which car travels farther farther and by how much​

Answers

Answered by mkjharavian
5

Explanation:

Speed of car P = 90 km/hr

Time = 6 secs

Distance travelled = Speed * Time

90 * 6 = 540km.

Speed of car Q = 54 km/hr

Time = 10 secs

Distance travelled = Speed * Time

54 * 10 = 540 km.

BOTH CARS HAVE TRAVELLED SAME DISTANCE.

Answered by neelamgarg091
0

Answer:

I don't know the answer of this question

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