Question

a car passes three points A,B And C at 5m/s , 10m/s, 15m/s respectively with uniformly acceleration. if AB=200m . find BC?
(Need correct solution if found wrong,will be reported)​

Answer 1

ANSWER
Given velocity of the car at point A v=20m/s and velocity of the car at point B u=30m/s.
And the distance between A and B = s
From equation of motion we get,
v
2
=u
2
​
+2as
as=250m/s----(1)
Now at mid point of AB s =
2
s
​

so velocity of the body at mid point of AB will be,
v
m
2
​
=u
2
+2a
2
s
​

Now putting the value of 1 in the above equation we get
v
m
2
​
=30
2
+250
v
m
​
=
1150
​
=33.91m/s