Question

a car passes three points A,B And C at 5m/s , 10m/s, 15m/s respectively with uniformly acceleration. if AB=200m . find BC?
(Need correct solution if found wrong,will be reported)​

Answer 1

Bro I'm intimidated by your last line but I'll try ;D

Since acc is uniform, we can use 3rd eq of motion:

$\frac{v^2-u^2}{2s}=a$

For BA, s=200 and v=10 while u=5. Plug these in:

$\frac{100-25}{2*200}=a\\a=\frac{75}{400}=\frac{3}{16}m/s^2$

Now, use this result for BC:

In another 3rd eq for motion we use v=15 (at C), u=10(at B) and s=BC:

$\frac{v^2-u^2}{2a}=s\\\frac{15^2-10^2}{2(3/16)}=s\\s=\frac{25}{3/8}\\s=\frac{200}{3}m$

Hence, BC=200/3 metres or 66.67m

Answer 2

There is slight mistake in above ans use 15^2 as 225 in last numerical and you'll gt correct sol.