a car pulled by a force of 200 n on a road with a uniform velocity how much frictional force will be acting between the car and the earth
Answers
Answer:
a car pulled by a force of 200 n on a road with a uniform velocity how much frictional force will be acting between the car and the earthquake
solution :
Forn object to move with constant velocity, net external force experienced by it must be equal to ZERO i.e F
external
=0
Thus a friction of 200 N must be exerted on the cabinet so that it moves with a constant velocity under the applied horizontal force of 200 N.
Explanation :
The cabinet will move with constant velocity only when the net force on it is zero. As the velocity of the cabinet is constant, its acceleration ought to be zero. Therefore, the active force acting on it is also zero. This implies that the magnitude of opposing frictional force is equal to the force exerted on the cabinet, which is 200 N. Therefore, the total friction force is -200 N.
Therefore, the force of friction on the cabinet = 200 N, in a direction opposite to the direction of motion of the cabinet.