Question

A car reached at a point A at 1.p.m. When it was traveling at a speed of 40 km/hour . Had it travelled 10 km/h faster, it would have reached at 12 noon. Find the distance covered by the car

Answer 1

It travelled 10 km/h faster, it would have reached at 12 noon, then the distance covered by the car is 200 km.

Step-by-step explanation:

Required Formula:

Time = [Distance] / [Speed]

When the speed of the car is 40 km/hr, it reaches point A at 1 p.m.

And,

When the speed of the car is 10 km/hr faster than the previous speed i.e., 40+10 = 50 km/hr, then the car reaches point A at 12 noon.

So, the time difference between 12 noon and 1 p.m. = 1 hr

Let the distance covered by the car be “d” km.

According to the question and based on the formula, we can write the equation as,

$\frac{d}{40} - \frac{d}{50} = 1$

⇒ d [$\frac{50 - 40}{40 * 50}$] = 1

⇒ d [$\frac{10}{2000}$] = 1

⇒ d = $\frac{2000}{10}$

⇒ d = 200 km

Thus, the distance covered by the car is 200 km.

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