A car reached from raipur to somgarh in 35 mins with an avg speed of 69km/hr if the avg speed is increased by 36km/hr how much time taken to cover the same distance
Answers
Answered by
1
average speed = d/t
69=d/time in hour
35minutes=7/12h
69=d/7/12
d=40.25km
new speed = 69+36=105
n.s.=40.25/time taken
105=40.25/t
t= 40.25/105
t= 0.38hr
t=22.8min
69=d/time in hour
35minutes=7/12h
69=d/7/12
d=40.25km
new speed = 69+36=105
n.s.=40.25/time taken
105=40.25/t
t= 40.25/105
t= 0.38hr
t=22.8min
Answered by
0
Old Time = 35 minutes = 7/12 hours
Old Speed = 69km/hr
New Speed = 69+36=105km/hr
Let distance be x
Old Time = x / 69
New Time = x/105
But given in question:
Old time= 7/12 hrs
So, x/69 = 7/12
x = 40.25
New Time = x/105 = 40.25/105 = 0.38 hours
0.38 hours = 22.8 minutes
ANSWER: 22.8 minutes
Mark BRAINLIEST And if possible FOLLOW...
Old Speed = 69km/hr
New Speed = 69+36=105km/hr
Let distance be x
Old Time = x / 69
New Time = x/105
But given in question:
Old time= 7/12 hrs
So, x/69 = 7/12
x = 40.25
New Time = x/105 = 40.25/105 = 0.38 hours
0.38 hours = 22.8 minutes
ANSWER: 22.8 minutes
Mark BRAINLIEST And if possible FOLLOW...
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