Question

A car requires 108 litres of petrol for covering a distance pf 594 km. How much petrol will be required by the car to cover 1650 km?​

Answer 1

Step-by-step explanation:

Given, diesel required for 594km = 108ldiesel required for 1km=\frac{108}{594}l\ =\frac{108\div54}{594\div54}=\frac{2}{11}l 594108 l = 594÷54108÷54 = 112

Given, diesel required for 594km = 108ldiesel required for 1km=\frac{108}{594}l\ =\frac{108\div54}{594\div54}=\frac{2}{11}l 594108 l = 594÷54108÷54 = 112 l

Given, diesel required for 594km = 108ldiesel required for 1km=\frac{108}{594}l\ =\frac{108\div54}{594\div54}=\frac{2}{11}l 594108 l = 594÷54108÷54 = 112 ldiesel required for 1650km=\frac{2}{11}\times1650l=2\times150=300l

Given, diesel required for 594km = 108ldiesel required for 1km=\frac{108}{594}l\ =\frac{108\div54}{594\div54}=\frac{2}{11}l 594108 l = 594÷54108÷54 = 112 ldiesel required for 1650km=\frac{2}{11}\times1650l=2\times150=300l 11

Given, diesel required for 594km = 108ldiesel required for 1km=\frac{108}{594}l\ =\frac{108\div54}{594\div54}=\frac{2}{11}l 594108 l = 594÷54108÷54 = 112 ldiesel required for 1650km=\frac{2}{11}\times1650l=2\times150=300l 112

Given, diesel required for 594km = 108ldiesel required for 1km=\frac{108}{594}l\ =\frac{108\div54}{594\div54}=\frac{2}{11}l 594108 l = 594÷54108÷54 = 112 ldiesel required for 1650km=\frac{2}{11}\times1650l=2\times150=300l 112

Given, diesel required for 594km = 108ldiesel required for 1km=\frac{108}{594}l\ =\frac{108\div54}{594\div54}=\frac{2}{11}l 594108 l = 594÷54108÷54 = 112 ldiesel required for 1650km=\frac{2}{11}\times1650l=2\times150=300l 112 ×1650l=2×150=300l