Question

A car rounds an unbanked curve of radius 92 m without skidding at a speed of 26 ms⁻¹. The smallest possible coefficient of static friction between the tyres and the road is 


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Answer 1

Answer:

92×26 ms-1=2,392

Explanation:

it is trying only

Answer 2

GivEn :

• Radius of the unbanked curve, r= 92 cm.

• Speed (v) = 26 m/s.

• We'll take acceleration due to gravity as, g = 9.8 m/s².

To find :

The smallest possible coefficient of static friction between the tyres and the road is (Coefficient of static friction)

Solution :

In order to calculate the coefficient of static friction we know need to know what is the coefficient of static friction all about!

So,

The coefficient of static friction is the friction force between any two bodies if neither of the bodies is moving, that is, isn't in motion.

Coefficient of static friction is given as :

» v = √μ(s)rg

where,

• v = final velocity

• μ(s) = coefficient of static friction

• r = radius

• g = acceleration due to gravity

Now, substituting the values :

=> v = √μ(s)rg

=> 26 = √μ(s) × 92 × 9.8

=> 26 = √μ(s) × 901.6

=> 26 = 30.02√μ(s)

=> √μ(s) = 26/30.02

=> √μ(s) = 0.86

=> μ(s) = (0.86)²

=> μ(s) = 0.739 (approx.)

$\therefore$The smallest possible coefficient of static friction between the tyres and the road is (Coefficient of static friction) is 0.739