Question

A car running at 20 ms-1slows down to 5 ms-1 by the application of brakes

over a distance of 30 m. Calculate the deceleration of the car.​

Answer 1

${ \mathtt \color{red}{given: }} \\ u = 20m {s}^{ - 1} \\ v = 5 m {s}^{ - 1} \\ s = 30m \\ \\ {\red {\mathtt{solution:}}} \\ \color{purple}{ {v}^{2} - {u}^{2} = 2as } \\ {5}^{2} - {50}^{2} = 2 \times a \times 30 \\ 25 - 2500 = 60 \times a \\ - 2475 = 60 \times a \\ a = \frac{ - 2475}{60} \\ a = - 41.25m {s}^{2}$

$\huge \mathfrak \color{purple}{thnq}$