Question

A car running at 72 km/h is slowed down to18km/h by the application of brakes over a distance of 12.5 m. Then total time in which car stops in sec is

Answer 1

hey maye
$72 - 18 \times 12.5$
$72 - 18 = 54$
$\frac{54}{1} \times \frac{125}{10}$
$\frac{6750}{10}$
$answer \: = 675$
hope it helps ♥️