A car runs a race at a distance of 22km along a circular path and reaches a diametrically opposite end in 3 minutes and
20 seconds. Calculate a velocity of car in meters/sec? no need i got the answer cani say Radius of lap = 100m
Circumference =2πR=200π=628m
time taken to cover one lap = 62.8s
Hence average speed =62.8628=10ms−1
Average velocity = 0 as the inital and final positions are same (after completing a lap) (displacement = 0)
Answers
Answer:
Explanation:
The diameter of the circular track is given as 200 m. That is, 2r=200 m.
From this radius is calculated as Radius, r = 100 m.
In 40 sec the athlete complete one round. So, in 2 mins and 20 secs, that is, 140 sec the athlete will complete = 140 / 40 = 3.5 (three and a half) rounds.
One round is considered as the circumference of the circular track.
The distance covered in 140 sec = 2πr×3.5=2×3.14×100×3.5=2200 m.
For each complete round the displacement is zero. Therefore for 3 complete rounds, the displacement will be zero.
At the end of his motion, the athlete will be in the diametrically opposite position. That is, displacement = diameter = 200 m.
Hence, the distance covered is 2200 m and the displacement is 200 m.
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