a car runs at a constant speed on a circular track of radius 200m taking 62.8s on each lap find the average speed and average velocity at each lap
Answers
Answered by
35
average speed means total distance covered by particle per interval of time .
e.g
average speed =total distance/total time
= 2π(200)/62.8
=2 × 314 /62.8 =10 m/s
average velocity = total displacement covered per unit time
e.g
average velocity= displacement/time
but we know if any particle moves in circular path and complete the revolution then, displacement is equal to zero.
now,
average velocity =0/ 62.8 =0
e.g
average speed =total distance/total time
= 2π(200)/62.8
=2 × 314 /62.8 =10 m/s
average velocity = total displacement covered per unit time
e.g
average velocity= displacement/time
but we know if any particle moves in circular path and complete the revolution then, displacement is equal to zero.
now,
average velocity =0/ 62.8 =0
Answered by
15
Total Distance = 2πr
= 2×(22/7)×200
= 8800/7 m
Displacement = 0 m
Time = 62.8 sec
Average Speed = Total Distance/Total Time
= (8800/7) ÷ 62.8
= 20 m/s (approx)
____________________________
Average Velocity = Total Displacement/Total Time
= 0/62.8
= 0 m/s
===============================
= 2×(22/7)×200
= 8800/7 m
Displacement = 0 m
Time = 62.8 sec
Average Speed = Total Distance/Total Time
= (8800/7) ÷ 62.8
= 20 m/s (approx)
____________________________
Average Velocity = Total Displacement/Total Time
= 0/62.8
= 0 m/s
===============================
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