Question

A car runs at a constant speed on a circular track of radius 150m taking 62.8s on each leap. The average speed and average velocity on each complete lap is? (π=3.14)​

Answer 1

Answer:

Average speed of the car is 15m/s

Average velocity of the car is 0m/s.

Explanation:

According to the Question

It is given that ,

• Radius of circular track ,r = 150m
• time taken ,t = 62.8s
• π = 3.14

We need to calculate the average Speed and average velocity on each complete lap.

Firstly we calculate the average Speed of the car.

As we know that average Speed is calculated by the sum of total distance divided by total time taken.

• Av.Speed = Total Distance/Total Time

Substitute the value we get

➻ Av.Speed = 2πr/total time

➻ Av.Speed = 2×3.14×150/62.8

➻ Av.Speed = 942/62.8

➻ Av.Speed = 15m/s

• Hence, the average Speed of the car is 15m/s.

Now, calculating the average velocity of the car.

As we know that average velocity is calculated by the total displacement divided by total time taken.

Since the car start from initial position and reach to its final position . (Final position means it again reached its initial position ). So ,the displacement of the car is 0 .

• Therefore, average velocity of the car is 0m/s.

Answer 2

$\huge \rm {Answer:-}$

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$\tt \pink {Given:-}$

★Radius(R) of circular track at which car runs at constant speed =150m

★Time taken by the car on each lap=62.8 seconds.

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$\tt \blue {To\: find-}$

★The average speed on each complete lap=?

★The average velocity on each complete lap=?

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★As the radius of the lap is given,we can find the circumference of the lap

$\dashrightarrow \tt {Circumference=2πR}$ [π=3.14]

$\dashrightarrow \tt {Circumference=2\times3.14\times150m}$

$\dashrightarrow \tt {Circumference=300m\times3.14}$

$\tt {\fbox{Circumference=942m}}$

★This is considered as the total distance covered by the car

★Time taken=62.8

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$\tt \blue {We\: know}$

$\to {Average\: speed=\frac{Total\: Distance}{Total\: Time}}$

$\to {Average\: speed=\frac{942m}{62.8s}}$

$\tt {\fbox{Average\: speed=15m/s}}$

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$\tt \orange {Average\: velocity}$

★Average velocity,here in this case is considered as "zero" as the displacement is zero because the initial and final positions are the same as it is a circular track.

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$\tt \purple {There,upon}$

$\tt {\fbox{Average\: speed=15m/s}}$

$\tt {\fbox{Average\: velocity=0}}$