Question

A car’s engine provides a forward force of 500 N. It is opposed by a resistive force of 200 N. The car accelerates forwards for 20 m. How much work is done by each force? By how much does the car’s energy increase?

Answer 1

Answer:

Answer: 9.8 m/s/s, down

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Answer 2

Answer:

Work done by 500N force is 10,000J.

Work done by resistive force of 200N is -4000J.

Increase in energy of car IS 6000J.

Explanation:

Work = Force * Displacement

Thus,

Work done by 500N force

= (+500) * 20

= 10,000 J

Work done by resistive force of 200N

= (-200) * 20

= - 4000J

By Work-Energy Theorem,

Total work done by a particle = change in kinetic energy of the particle,

Thus,

Increase in energy of car

= 10,000 - 4000

= 6000 J