A car slows down from 108kmh with a uniform retardation of 5ms². How long will it take to reach 18kmh ,and what will be the distance covered
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Answer:
t=5s. s= 87.5m
Explanation:
a= v-u/t
-5t = 5-30
t = 5s
s= ut+1/2at^2
substitute values
s = 87.5m
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