Question

A car slows down from 50.0 m/s to 20.0 m/s in 6.0 s. What is the acceleration?

Answer 1

Answer:

5 m/s^2

Explanation:

a= v-u /t

a= 50 - 20/6

=30/6 m/s^2

= 5 m/s^2

Answer 2

★ Answer :

• $\boxed{\textsf{\textbf{Acceleration (a) = -5 m/s ^\text 2 }}}$

★ Given :

• Initial velocity (u) = 50 m/s
• Final velocity (v) = 20 m/s
• Time taken (t) = 6 seconds

★ To Find :

• Acceleration (a) of the car

★ Explaination :

From equation of motion we have :

• $\boxed{ \textsf{\textbf{v = u + at}}}$

By substituting value of v, u & t in the equation we get :

$:\implies\sf 20 = 50 + a(6)$

$:\implies\sf 6a + 50 = 20$

$:\implies\sf 6a = 20 - 50$

$:\implies\sf 6a = - 30$

$:\implies\sf a = - \dfrac{30}{6}$

$:\implies\underline{\boxed{\sf a = -5 \: m/s^2}}$

⛬ Acceleration (a) of the car = -5 m/s².