Question

A car slows down uniformly from a speed of 20.0 m/s to rest in 7.20 s .

How far did it travel in that time?

Answer 1

intial velocity (u)=20

final velocity (v)= 0

time =7.20 seconds

now first we need to calculate acceleration

we know

v=u +at

a= v-u/t

a= -20/7.20

now second equation

s=ut+1/2 at^2

20 * 7.20 + (1/2) * (-20/7.20) * 7.20^2= 72

so distance is 72 m