Question

a car sold for rs23800 on 15 % discount ..what was its orignal price​

Answer 1

Let the original price be rs x

and the discounted price be rs y

so,

as given

selling price (rs23800) = original price - discounted price

so,

x - y = 23800---------eq 1

now, we know that

15% of x = y

15/100 × x = y

x = 20y/3

put this value on eq1

x - y = 23800

20y/3 - y = 23800

(20y - 3y)/3 = 23800

17y = 71400

y = 71400/17

y = 4200

hence discounted price is rs 4200

now put this value in eq 1 to find original price of car

x - y = 23800

x = 23800 + y

x = 23800 + 4200

x = 28000

therefore the original price of car is rs 28000

Answer 2

The original price of car was Rs 28000

Step-by-step explanation:

Let original price of a car be x

15% discount on car

Price of of car after discount = x - 15% of x

Therefore,

x - 0.15x = 23800

   0.85x = 23800

           x = 28000

The original price of car is Rs 28000

#BAL

#ANSWERWTIHQUALITY