Question

A car speed increases from 40 km per hour to 60 kilometre per hour in 5 second calculate the acceleration

Answer 1

Solution :

⏭ Given:

✏ Initial velocity of car = 40kmph

✏ Final velocity of car = 60kmph

✏ Time interval = 5s

⏭ To Find:

✏ Acceleration of car

⏭ Conversation:

• 40kmph = 11.11mps
• 60kmph = 16.67mps

⏭ Concept:

✏ Acceleration is defined as ratio of change in velocity to the time interval.

⏭ Calculation:

$\implies \sf \: \red{a = \frac{v - u}{ t}} \\ \\ \implies \sf \: a = \frac{16.67 - 11.11}{5} \\ \\ \implies \sf \: a = \frac{5.56}{5} \\ \\ \implies \: \boxed{ \tt{ \green{a = 1.11 \: m {s}^{ - 2} }}}$

⏭ Additional information:

• Acceleration is a vector quantity.
• Vector quantity has both magnitude as well as direction.

Answer 2

$\tt{\huge{\pink{Hello!!! }}}$

Question :

A car speed increases from 40 km per hour to 60 kilometre per hour in 5 second calculate the acceleration.

Conversion :

• 40km/hr = 11.11m/s

• 60km/hr = 16.67m/s

Solution :

We Know That :

$\tt{ \purple{ \leadsto \: {a \: = \dfrac{v - u}{t} = 1.11 \: m . {s}^{-2} }}}$