Question

A car speeds up from 12 m per second to 20 m per second in 6.4 seconds. If its mass is 1200 kg what force must its engine provide?

Answer 1

F=ma

m=mass of car=1200 kg
a=acceleration of car

u, initial speed = 12 m/s
v,final speed =20 m/s
t,time taken to achieve final speed= 6.4 secs

a=v-u/t=8/6.4 m/s^2

Force to be provided

F= 1200*8/6.4 N

Answer 2

Answer:

Acceleration =( final velocity - initial velocity) /time

a=( 20-12)/6.4 =1.25 m/s^2

Assuming that the air resistance is negligible, we can use this formula Force =mass x acceleration

Plugging values in will give us 1200 x 1.25 = 1500 N

So the force the engine has to provide is 1500 N.