A car speeds up from 12 m/s to 20 m/s
in 6.4s. If its mass is 1200 kg, what force
must its engine provide?
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- We might know that the greater the acceleration of, say, a car moving away from a stop sign, the greater the displacement in a given time. But we have not developed a specific equation that relates acceleration and displacement. In this section, we develop some convenient equations for kinematic relationships, starting from the definitions of displacement, velocity, and acceleration already covered.
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Acceleration =( final velocity - initial velocity) /time
a=( 20-12)/6.4 =1.25 m/s^2
Assuming that the air resistance is negligible, we can use this formula Force =mass x acceleration
Plugging values in will give us 1200 x 1.25 = 1500 N
So the force the engine has to provide is 1500 N.
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