Question

A car sta A car starts from rest with constant acceleration of 2 metre per second square at same instant a bus travelling with a uniform velocity of 10 metre per second overtakes the car the car miss the bus again after time

Answer 1

Answer:

the car miss the bus after 2.03s

Explanation:

When the bus will just pass the distance covered will be equal

Case 1-

S1 = distance cover by car

S2 = distance cover by bus

S1 = v1^2/a = v1^2 /2

S2 = u2^2 = 100

S1 = S2

V1^2/2 = 100

V1 = 10√2 m/s = 14.14m/s

Case 2 -

the final velocity in case 1 can be initial velocity in case 2

S1 = v1^2 - u1^2/a = v1^2 - 200/2

S2 = u^2 = 100

S1 = S2

V1^2 - 200 = 2 x 100

V1^2 = 400

V1 = 20m/s

V1 = U1 + at

20 - 10√2 = 2t

t = 10 - 5√2 = 10 - 7.07

t = 2.03s

At this they will at same position ,

so the car miss the bus after 2.03s

if it is right plz appreciate because it needs lot of hardwork and time to write in mobile comparatively on notebook.

if it is wrong plz let me know in comments section.