A car Start from and acquires a velocity of 54 km / h in 2 minute find acceleration and distance travelled by the car during this time
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u=0m/s
v=54km/h=54×5/18=15m/s.
time=2 min=2×60=120
acce. =v-u/t
=15-0/120
=15/120
=0.125m/s^2
Distance=2as=v^2-u^2
2×0.125×s=15^2-0^2
0.25s=225-0
0.25s=225
s=225/25×100
s=900.
May this help u
v=54km/h=54×5/18=15m/s.
time=2 min=2×60=120
acce. =v-u/t
=15-0/120
=15/120
=0.125m/s^2
Distance=2as=v^2-u^2
2×0.125×s=15^2-0^2
0.25s=225-0
0.25s=225
s=225/25×100
s=900.
May this help u
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