Question

A car start from rest and acquire a velocity of 54 km/h in 2 sec. Find
(i) the acceleration 
(ii) distance travelled by car assume motion of car is uniform?

Answer 1

Hey user here is Answer

According to question

Given that

v=54km/h

v=54×1000/60×60 m/s

v=540/36

v=90/6

v=15 m/s

t=2 s

(1)

a=?

using this formula

v=u+at

15=0+2a

2a=15

a=15/2

a=7.5 m/s^2

(2)

s=?

s=ut+1/2at^2

s=0×2+1/2×7.5×2×2

s=15 m

thanks for asking

Answer 2

Answer:

As the car is starting from rest ,

Initial velocity = u = 0 m/s

Final velocity = v = 54 km/hr

To convert km/hr to m/s , we multiply it by 5/18

Final velocity = v = 54 km/hr = 54 x 5/18

= 15 m/s

Time = t = 2 sec

a = acceleration

Equation of motion :

v = u + at

15 = 0 + 2a

a = 15/2 = 7.5 m/s²

s = distance traveled

Equation of motion :

s = ut + 1/2 at²

= 0 + 1/2 × 7.5 × 2²

= 15 metres