Question

A car start from rest and acquire a velocity of 54 km/h in 2 sec. Find
(i) the acceleration
(ii) distance travelled by car assume motion of car is uniform?​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Acceleration=7.5\:m/s^{2}}}}$

$\green{\tt{\therefore{Distance=15\:m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given:}} \\ \tt: \implies Initial \: velocity(u) = 0\: km/h \\ \\ \tt: \implies Final \: velocity( v ) = 54 \: km/h \\\\ \tt: \implies Time( t) = 2 \: sec \\ \\ \red{\underline \bold{To \: Find:}}\\ \tt: \implies Acceleration(a) = ?\\\\ \tt:\implies Distance\:travelled=?$

• According to given question :

$\tt \circ \: Initial \: velocity =0 \: m/s \\ \\ \tt \circ \: Final \: velocity = 54\times \frac{5}{18}=15 \: m/s \\ \\ \tt \circ \: Time = 2\: sec \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies 15= 0 + a \times 2 \\ \\ \tt: \implies 15 = 2 \times a \\ \\ \tt: \implies a = \frac{15}{2} \\ \\ \green{\tt: \implies a =7.5 \: m/{s}^{2} }$

$\bold{As \: we \: know \: that} \\ \tt: \implies s = ut + \frac{1}{2} a {t}^{2} \\ \\ \tt: \implies s = 0 \times 2 + \frac{1}{2} \times 7.5 \times {2}^{2} \\ \\ \tt: \implies s = \frac{1}{2} \times 7.5 \times 4 \\ \\ \green{\tt: \implies s = 15 \: m}$

Answer 2

$</p><p>\tt{\huge{\pink{Hello!!!! }}}$

$</p><p>\tt{\red{Given \: - }}$

A car start from rest and acquire a velocity of 54 km/h in 2 sec.

$</p><p>\tt{\orange{Step-By-Step-Explaination \: - }}$

$</p><p>\tt{\boxed{\boxed{\purple{A = \dfrac{V-U}{t} = 7.5 \: m/{s}^2 }}}} ...........(A)$

By the Second Equation Of Motion ;

$</p><p>\tt{\boxed{\boxed{\blue{S \: = \: UT \: + \: \dfrac{1}{2} A {T}^2 = 15 \: m. }}}} ............(A)$