Question

A car start from rest and acquire a velocity of 54 km/h in 2 sec. If the mass of the car is 1000 Kg . Find the force acting on it?

Answer 1

Answer:-

Given:

Initial velocity (u) = 0 m/s.

[ since , the car has started from rest position ]

Final velocity (v) = 54 km/h = 54 * 5/18 m/s = 15 m/s.

Mass of the car (m) = 1000 kg

Time(t) = 2 s.

We know that,

Force (F) = mass * acceleration.

• Acceleration = (v - u)/t.

⟹ F = m * (v - u)/t

⟹ F = 1000 * (15 - 0)/2

⟹ F = 1000 * 15/2

⟹ F = 7500 N

∴ The force acting on the car is 7500 N.

Answer 2

Answer:

$\underline{\boxed{\red{\bf Force = 7500 \: N}}}$

Explanation:

Since the car started from the rest, the initial velocity of the car must be 0 m/s.

⇒ Final velocity = 54 km/hr

Converting km/hr into m/s,

⇒ v = 54 * $\dfrac{5}{18}$ = 15m/s.

Mass given, m = 1000 kg.

Now we've,

• u = 0 m/s
• v = 15 m/s
• t = 2 sec
• m = 1000 kg

We know that ;

★ $\boxed{\bf Acceleration = \dfrac{v-u}{t}}$

$\sf \implies a = \dfrac{15-0}{2}$

$\sf \implies a = \dfrac{15}{2} \: m/s^2$

Now,

★ $\boxed{\bf Force = Mass * Acceleration}$

$\sf \implies Force = 1000 * \dfrac{15}{2}$

$\sf \implies Force = 500 * 15$

$\sf \implies Force = 7500 N$

Thus, the force acting on it is 7500 N.