A car start from rest and acquire a velocity of 54 km/h in 2 sec. Find(i) the acceleration(ii) distance travelled by car assume motion of car is uniform?
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Answer:
Explanation:
for acceleration
a= v -u/t
a= 54 -0/2
2
a= 27 m/s
for distance
s = ut + 1/2 at×t
s= 0 × 2 + 1/2 × 27×2×2
s= 0 + 1/2 × 108
s = 2+1/2 × 108
s= 3/2 × 108
s= 162 m
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