. A car start from rest and acquire a velocity of 54 km/h in 2 sec. Find (i) the acceleration
(ii) distance travelled by cat assume motion of car is uniform
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54km/hr=5/18 × 54m/s
=15m/s
V=u+at
15=0+2a
a=7.5m/s^2
Now
s=ut+1/2 at^2
=1/2×7.5×4
=15m
=15m/s
V=u+at
15=0+2a
a=7.5m/s^2
Now
s=ut+1/2 at^2
=1/2×7.5×4
=15m
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