Question

A car start from rest and acquire a velocity of 54km/h 2sec. find(I) the acceleration (ii) distance traveled by car assume motion of car is uniform (iii)if the mass of the car is 1000kg, what is force acting on it​

Answer 1

Given that,

Intial velocity u=0m/s

Final velocity v=54km/h=54×

18

5

=15m/s

Time t=2min=120s

Now, put the value in equation of motion

The acceleration is

v=u+at

a=

t

v−u

a=

120

15−0

a=o.125m/s

2

Now, again from equation of motion

The distance is

s=ut+

2

1

at

2

s=0+

2

1

×0.125×120×120

s=900m

Hence, the acceleration is 0.125m/s

2

and distance is 900m

Explanation:

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