Question

A car start from rest and acquire a velocity of 54km h,l in 2 minutes. Find
1. the acceleration 2. distance travelled by car during this time

Answer 1

Answer:

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Answer 2

Hey mate

Step-by-step explanation:

Given u=0 (as car starts from rest)

v=54 km/h= 54×5/18m/s

v= 15 m/s

Time (t) =2 minutes

= 2×60 = 120 seconds

1. from first equation of motion

v=u+at

15=0+a(120)

15=120a

a=15/120=1/80

acceleration =1/80 m/s^2

2. From second equation of motion

s=ut+1/2at^2

s=0(120)+1/2(1/80)×(120)^2

s = 0+1/160×120×120

s = 1/160×14400

s = 14400/160

s=720/8

distance=90 metres

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