Question

A car start from rest and attain a velocity of 20 m/s in 5 s. Calculate the distance during the time​

Answer 1

The car traveled 50 m while accelerating from 0 to 20 m/s in 5 seconds.

The distance d is from

d = v(avg) • t

where v(avg) is the average velocity during the time, or

v(avg) = v(initial) + ∆v/2.

Here v(initial) is 0 and ∆v is 20 m/s, so

v(avg) = 20 m/s / 2 = 10 m/s.

d = 10 m/s • 5 s = 50 m.

Answer 2

Answer:

50 metres

Explanation:

Given: final velocity = v = 20m/s

initial velocity = u = 0 m/s

time = t = 5s

Now, v = u + at

20 = 0 + a5

20 = a5

a = 20/5 = 4m/s^2

Therefore, distance = s = ?

acceleration = a = 4m/s^2

S = ut + 1/2at×t

= 0×5 + 1/2 × 4× 5 ×5

= 0 + 2× 25

= 50 m

The total distance travelled by the car is 50 m.