Question

a car start from rest and moves along with X-axis with constant acceleration 5m/s² for 8second. if it then continues with constant velocity
what distance will car cover in 12second since its started from rest

Answer 1

Hey.

Here is the answer.

u = 0

a = 5 m/s^2

t1 =8 sec

so, v = u + a t

or, v = 0 + 5×8 =40 m/s

so, s = u t + 1/2 a t^2

or, s1 = 0 + 1/2 ×5× 8^2 = 160 m

from 8s to 12s (12-8=4s) , distance covered with uniform velocity v = 40m/s

so, s2= 40×4 = 160 m

s = s1 + s2 =160+160=320 m

Hence , distance covered in 12s from start is 160m.

Thanks.