Question

A car start from rest for 10sec. at the rate of 0.3m/s2. Determine its final velocity

Answer 1

Answer:

10 velociry like brilintest make an offer

Answer 2

Acceleration, a = 5 m/s

initial velocity, u = 0

final velocity, v = ?

Second Equation Of Motion Formula :

$\begin{gathered}\begin{gathered}\mapsto \sf\boxed{\bold{\green{s =\: ut + \dfrac{1}{2} at^2}}}\\\end{gathered}\end{gathered}$

$0 + \frac{1}{2} + 5 \times (10) {}^{2} \\ s1 = 250m$

Now, it attains constant speed

First Equation Of Motion Formula :

$\begin{gathered}\begin{gathered}\mapsto \sf\boxed{\bold{\pink{v = u + at}}}\\\end{gathered}\end{gathered}$

v = 0 + 5 × 10

v = 50 m/s

Let's calculate distance after 10 sec

$\begin{gathered}\begin{gathered}\mapsto \sf\boxed{\bold{\blue{s =\: ut + \dfrac{1}{2} at^2}}}\\\end{gathered}\end{gathered}$

s 2 = 50 × 10 + 1/2 × 0 × (10)^2

s 2 = 500

Add s1 and s2

250 + 500

750 m