Question

a car start from rest it aquire speed of 25 ms-1 after 20 s the distance moved by the car during this time ..
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Answer 1

Explanation:

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Answer 2

Answer:

Initial speed, u = 0

Final speed, v = 25 m/s

Time, t = 20 s

To find,

The distance moved by the car.

Solution,

Firstly, finding the acceleration of the car as :

\begin{gathered}a=\dfrac{v-u}{t}\\\\a=\dfrac{25}{20}\\\\a=1.25\ m/s^2\end{gathered}a=tv−ua=2025a=1.25 m/s2

Let d is the distance moved by the car during this time. Using second equation of motion to find it as :

\begin{gathered}d=ut+\dfrac{1}{2}at^2\\\\d=\dfrac{1}{2}\times 1.25\times (20)^2\\\\d=250\ m\end{gathered}d=ut+21at2d=21×1.25×(20)2d=250 m

So, the distance moved by the car during this time is 250 meters.