Question

a car start from rest it cover distance of 25m in 4s then find its acceleration

Answer 1

Given
U=0
T=4s
S= 25m
from motion equation
S = ut + 1/2a× t×t
= 0 + 1/2 × a× 4×4
= 8a
25 = 8a
then a = 25/8
= 3.125m/s^2

Answer 2

We know that,
S=ut+1/2at^2

Since
S=25m
u=0
T=4sec

Therefore
25=0*4+1/2*a*4*4
》25=0+8a
》a=25/8
》a=3.125m/s^2

Hope it helps....