Question

A car start from rest moves with uniform acceleration .the car travels 100m in 5s. what is its final velocity

Answer 1

Answer:

It's final velocity is 40 m/s.

Explanation:

initial velocity u = 0

distance S = 100 m

time taken t = 5 sec

Using 2nd equation of motion,

S = ut + 1/2 at^2

100 = 0 × 5 + 1/2 × a × ( 5 )^2

100 = 1/2 a × 25

Acceleration a = ( 100 × 2 ) / 25

= 8 m/s

Now, using 1st equation of motion,

v = u + at

Final velocity v = 0 + 8 × 5

= 40 m/s

Answer 2

Answer:

Final velocity = 40m/s

Explanation:

Given -

• Initial velocity (u) =0m/s
• Distance (s) = 100m
• Time (t) = 5 seconds

Solution -

To find the final velocity, we'll have to find the acceleration first.

• s=ut+1/2at²
• 100=(0×5)+1/2a5²
• 100= 25a/2
• 200/25=a
• 8=a

Acceleration = 8m/s²

Final velocity -

• v=u+at
• 0+(8×5)
• 40 m/s
• Final velocity is 40m/s .