Question

A car start from rest with uniform acceleration 3m/s Square along straight line find the distance moved by car in 15 sec
​

Answer 1

$\huge\red{@nswer}$

Given that,

Time t=10sec

Velocity v=12km/h=

18

12×5

m/s

Now, the acceleration isUsing of equation of motion

v=u+at

12× 185 =0+a×10

a= 10×18

12×5

a= 31

m/s 2

Hence, the acceleration is

31 m/s 2

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