Math, asked by rssahu6988, 6 months ago

A car start moving from rest and a velocity of 10 m/s in 5 minutes time graph minutes if the acceleration is constant then calculate acceleration

Answers

Answered by llSecreTStarll
3

\underline{\underline{\red{\textbf{Step - By - Step - Explanation : -}}}}

To Find :

  • Acceleration of car .

Solution :

  • Velocity of car = 10m/s
  • Time taken = 5 minutes
  • initial velocity = 0
  • Acceleration = ?

Firstly we should convert Time minutes into Seconds.

Time = 5 minutes

Time = 5 × 60 Seconds

Time = 300 seconds

By using First equation of Motion :

v = u + at

›› 10 = 0 + a × 300

›› 10 = 300a

›› 10/300 = a

›› 1/30

›› 0.03 m/s²

Hence

  • Acceleration of car is 0.03m/

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Answered by Anonymous
5

Answer :

›»› The Acceleration of car = 0.03 m/s²

Given :

  • Initial velocity of a car = 0 m/s
  • Final velocity of a car = 10 m/s
  • Time taken by a car = 5 min

To Find :

  • Acceleration of a car = ?

Required Solution :

Before we start our solution, let's first we know about Acceleration.

The rate of change of the velocity of an object is known as Acceleration.

  • The SI unit of Acceleration is m/s².
  • The GGS unit of Acceleration is cm/s².
  • Acceleration is represented by a.

To find the Acceleration of car, at first we need to convert the Time taken by a car minutes into second, after that we will find Acceleration of car on the basis of conditions given above

◈ Time taken = 5 min

→ Time taken = 5 × 60

→ Time taken = 300 sec

We can find Acceleration of car by using the first equation of motion which says v = u + at.

Here

  • v is the Final velocity in m/s.
  • u is the Initial velocity in m/s.
  • a is the Acceleration in m/s².
  • t is the Time taken in second.

So let's find Acceleration (a) !

From first equation of motion

⇛ v = u + at

⇛ 10 = 0 + a × 300

⇛ 10 = 300a

⇛ 10/300 = a

⇛ 1/30 = a

⇛ 0.03 = a

⇛ a = 0.03 m/s²

Hence, the Acceleration of a car is 0.03 m/s².

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Some related equations :

⪼ First equation of motion :- v = u + at

⪼ Second equation of motion :- s = ut + ½ at²

⪼ Third equation of motion :- v² = u² + 2as

Where,

  • v is the final velocity in m/s.
  • u is the intial velocity in m/s.
  • a is the acceleration in m/s².
  • t is the time taken in m/s².
  • s is the distance in m.

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