A car start moving from rest and a velocity of 10 m/s in 5 minutes time graph minutes if the acceleration is constant then calculate acceleration
Answers
To Find :
- Acceleration of car .
Solution :
- Velocity of car = 10m/s
- Time taken = 5 minutes
- initial velocity = 0
- Acceleration = ?
Firstly we should convert Time minutes into Seconds.
Time = 5 minutes
Time = 5 × 60 Seconds
Time = 300 seconds
By using First equation of Motion :
v = u + at
›› 10 = 0 + a × 300
›› 10 = 300a
›› 10/300 = a
›› 1/30
›› 0.03 m/s²
Hence
- Acceleration of car is 0.03m/s²
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Answer :
›»› The Acceleration of car = 0.03 m/s²
Given :
- Initial velocity of a car = 0 m/s
- Final velocity of a car = 10 m/s
- Time taken by a car = 5 min
To Find :
- Acceleration of a car = ?
Required Solution :
Before we start our solution, let's first we know about Acceleration.
The rate of change of the velocity of an object is known as Acceleration.
- The SI unit of Acceleration is m/s².
- The GGS unit of Acceleration is cm/s².
- Acceleration is represented by a.
To find the Acceleration of car, at first we need to convert the Time taken by a car minutes into second, after that we will find Acceleration of car on the basis of conditions given above
◈ Time taken = 5 min
→ Time taken = 5 × 60
→ Time taken = 300 sec
We can find Acceleration of car by using the first equation of motion which says v = u + at.
Here
- v is the Final velocity in m/s.
- u is the Initial velocity in m/s.
- a is the Acceleration in m/s².
- t is the Time taken in second.
So let's find Acceleration (a) !
From first equation of motion
⇛ v = u + at
⇛ 10 = 0 + a × 300
⇛ 10 = 300a
⇛ 10/300 = a
⇛ 1/30 = a
⇛ 0.03 = a
⇛ a = 0.03 m/s²
║Hence, the Acceleration of a car is 0.03 m/s².║
Some related equations :
⪼ First equation of motion :- v = u + at
⪼ Second equation of motion :- s = ut + ½ at²
⪼ Third equation of motion :- v² = u² + 2as
Where,
- v is the final velocity in m/s.
- u is the intial velocity in m/s.
- a is the acceleration in m/s².
- t is the time taken in m/s².
- s is the distance in m.